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Question
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
Compare the distance travelled in part BC with the distance travelled in part AB.
Solution
Distance travelled in part BC = Area of the rectangle tBC2t = base × height.
= (2t - t) × vo
= vot
Distance travelled in part AB = Area of the triangle ABt
= (1/2) × base × height
= (1/2) × t × vo
= (1/2) vo t
Therefore, distance travelled in part BC:distance travelled in part AB :: 2:1.
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