English

A ball moves on a smooth floor in a straight line with uniform velocity 10 m s-1 for 6 s. At t = 6 s, the ball hits a wall and comes back along the same line to the starting point with the same speed. - Physics

Advertisements
Advertisements

Question

A ball moves on a smooth floor in a straight line with uniform velocity 10 m s-1 for 6 s. At t = 6 s, the ball hits a wall and comes back along the same line to the starting point with the same speed. Draw the velocity-time graph and use it to find the total distance travelled by the ball and its displacement.

Sum

Solution

Distance travelled in first 6 s = velocity × time

= 10 m/s × 6

= 60 m

Distance travelled in next 6 s = velocity × time

= 10 m/s × 6

= 60 m

Total distance travelled in 12 s = (60 + 60) m = 120 m

Total displacement = 0, as the ball returns its starting point.

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Motion in One Dimension - Exercise 2 (B) [Page 50]

APPEARS IN

Selina Concise Physics [English] Class 9 ICSE
Chapter 2 Motion in One Dimension
Exercise 2 (B) | Q 11 | Page 50
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×