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प्रश्न
A ball moves on a smooth floor in a straight line with uniform velocity 10 m s-1 for 6 s. At t = 6 s, the ball hits a wall and comes back along the same line to the starting point with the same speed. Draw the velocity-time graph and use it to find the total distance travelled by the ball and its displacement.
उत्तर
Distance travelled in first 6 s = velocity × time
= 10 m/s × 6
= 60 m
Distance travelled in next 6 s = velocity × time
= 10 m/s × 6
= 60 m
Total distance travelled in 12 s = (60 + 60) m = 120 m
Total displacement = 0, as the ball returns its starting point.
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संबंधित प्रश्न
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- Its magnitude is greater than the distance travelled by the object.
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| Time (s) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Distance travelled by A (m) | 0 | 20 | 80 | 180 | 240 | 300 | 360 | 420 |
| Distance travelled by B (m) | 0 | 10 | 40 | 90 | 160 | 250 | 360 | 490 |
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Which of the following is correct?
Using the following data, draw time - displacement graph for a moving object:
| Time (s) | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 |
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Use this graph to find average velocity for the first 4 s, for the next 4 s and for the last 6 s.
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Reason: Displacement is a vector & distance is a scalar quantity.
