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Question
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears a two-digit number,
Solution
Total number of discs = 90
Let E1 be the event of having a two-digit number.
Number of discs bearing two-digit number = 90 − 9 = 81
∴ P(getting a two-digit number) = P(E1) = `("Number of outcome favourable to" E_1)/"Number of all possible outcome "`
`= 81/90 = 9/10`
Thus, the probability that the disc bears a two-digit number is `9/10`
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