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Question
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears a perfect square number.
Solution
Total number of discs = 90
Let E2 be the event of getting a perfect square number.
Discs bearing perfect square numbers are 1, 4, 9, 16, 25, 36, 49, 64 and 81.
Number of discs bearing a perfect square number = 9
∴ P(getting a perfect square number) =
P(E2) = `("Number of outcomes favourable to E"_2)/"Number of all possible outcomes"`
P(E2) = `9/90`
∴ P(E2) = `1/10`
Thus, the probability that the disc bears a perfect square number is `1/10`
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