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Question
A can do a piece of work in 40 days and B in 45 days. They work together for 10 days and then B goes away. In how many days will A finish the remaining work?
Solution
LCM of 45 and 40 is 360. So let the work be of eating 360 chocolates. A finishes work in 40 days and B in 45, so A eats chocolates per day and B eats 8 chocolates per day. Together they work for 10 days and eat 17 chocolates each day.
Total chocolates eaten in 10 days = 170
Number of chocolates left = 360 − 170 = 190
A will eat 190 chocolates in ⇒ `190/9` = 21.1 days.
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