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A carpenter had a board which measured 3 m × 2 m. She cut out a rectangular piece of 250 cm × 90 cm. What is the ratio of the area of cut out piece and the remaining piece? - Mathematics

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Question

A carpenter had a board which measured 3 m × 2 m. She cut out a rectangular piece of 250 cm × 90 cm. What is the ratio of the area of cut out piece and the remaining piece?

Sum

Solution

The area of the board = 3 m × 2 m

= 6 m2 = 6 × 10000 cm2 

= 60000 cm2

And the area of cut out piece = 250 cm × 90 cm

= 22500 cm2

∴ The area of remaining piece = (60000 – 22500) cm2

= 37500 cm2 

Thus, the required ratio = `"The area of cut out piece"/"The area of remaining piece"`

= `(22500  cm^2)/(37500  cm^2) = 3/5` = 3:5

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Chapter 8: Ratio and Proportion - Exercise [Page 130]

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NCERT Exemplar Mathematics [English] Class 6
Chapter 8 Ratio and Proportion
Exercise | Q 89 | Page 130

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