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Length and breadth of the floor of a room are 5 m and 3 m, respectively. forty tiles, each with area 116 m2 are used to cover the floor partially. Find the ratio of the tiled and the non tiled port - Mathematics

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Question

Length and breadth of the floor of a room are 5 m and 3 m, respectively. forty tiles, each with area `1/16` m2 are used to cover the floor partially. Find the ratio of the tiled and the non tiled portion of the floor.

Sum

Solution

Given, Length of the floor of a room = 5 m

Breadth of the floor of a room = 3 m

Area of the room = Length × Breadth

= 5 × 3 = 15 m2

∵ Area of 1 title = `1/16` m2

∴ Area of 40 tiles = `1/16 xx 40` = 2.5 m2

Area covered by tiles = 2.5 m2

Area not covered by tiles = (15 – 2.5) = 12.5 m2

Ratio of the tiled to non-tiled portion = `(2.5  m^2)/(12.5  m^2) = 25/125 = 1/5` = 1.5

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Chapter 8: Ratio and Proportion - Exercise [Page 130]

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NCERT Exemplar Mathematics [English] Class 6
Chapter 8 Ratio and Proportion
Exercise | Q 88 | Page 130

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