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Question
A coin is tossed 8 times. In how many ways can we obtain 4 heads and 4 tails?
Solution
A coin is tossed 8 times. All heads are identical and all tails are identical.
We can obtain 4 heads and 4 tails in `(8!)/(4!4!)`
= `(8 xx 7 xx 6 xx 5 xx 4!)/((4 xx 3 xx 2 xx 1)4!)`
= 2 × 7 × 5
= 70 ways
∴ In 70 different ways, we can obtain 4 heads and 4 tails
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