Question

A cricket ball of mass 100 g strikes the hand of a player with a velocity of 20 ms^-1 and is brought to rest in 0.01 s calculate

1) the force applied by the hand of the player.

2) the acceleration of the ball

Answer 1

1) Mass of cricket ball, m = 100g = 0.1 kg

Δv = (v - u) = (0 - 20) = - 20 m/s

Time Δt = 0.01 s

F x Δt = Δp (change in momentum)

F = `(Δp)/(Δt) = (mΔv)/(Δt) = - (0.1 xx 20)/0.01 = - 200 N`

2) F = mass  x accelartion

F = m a

`a = F/m = (-200)/0.1 = -2000` ms^-2