Question

A cricket player holds a cricket ball of mass 100 g by moving his hands backward by 0.75 m. If the initial velocity of the ball is 108 kmh⁻¹, find the retarding force applied by the player.

Answer 1

Mass of ball – m = 100 g = 0.1 kg
Distance covered = S = 0.75 m
Initial velocity of ball = u = 108 kmh⁻¹

u = `108xx5/18` ms⁻¹ = 30 ms⁻¹

Final velocity of car = v = 0
Retarding force = F = ?
v² – w² = 2a S
(0)² − (30)² = 2a (0.75)
1.5 a = −900

a = `-900/1.5` = −600 ms⁻²

Retarding force = F = ma
F = 0.1 × (−600)
F = −60 N