Question

A dealer bought two tables for Rs 3120. He sold one of them at a loss of 15% and other at a gain of 36%. Then, he found that each table was sold for the same price. Find the cost price of each table.

Answer 1

$$\text{ Given that the selling price is same for both the tables }.$$

$$\text{ Let the C . P of 1 table be Rs . x, then the C . P of the other will be Rs }.(3120-x).$$

$$\text{ Loss on the first table = 15 \% }$$

$$\text{ Therefore, S . P = C . P }\left(\frac{100-\text{ loss \% }}{100}\right)$$

$$S.P=\frac{85x}{100}=Rs.0.85x$$

$$\text{ Gain on the second table = 36 \% }$$

$$\text{ Therefore, S . P = C . P }\left(\frac{100+\text{ gain \% }}{100}\right)$$

$$\text{ S . P = Rs . 1 . 36 }(3120-x)$$

$$\text{ Since both tables have the same S . P },$$

$$\text{ So,}0.85x=1.36(3120-x)$$

$$0.85x=4243.20-1.36x$$

$$2.21x=4243.20$$

$$x=\frac{4243.20}{2.21}$$

$$x=Rs.1920$$

$$\text{ So, the cost price of the first table is Rs }.1920.$$

$$\text{ Cost price of the second table = Rs }.(3120-1920)=Rs.1200$$