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Question
Mariam bought two fans for Rs 3605. She sold one at a profit of 15% and the other at a loss of 9%. If Mariam obtained the same amount for each fan, find the cost price of each fan.
Solution
\[\text { It is given that the S . P is same for both the fans } . \]
\[\text { Let C . P of the first fan be Rs . x }\]
\[\text { Therefore, C . P of the second fan = Rs }. (3605 - x)\]
\[\text { Profit on the first fan = 15 % } \]
\[\text { Loss on the second fan = 9 % } \]
\[\text { For the first fan }, \]
\[\text { S . P = C . P }\left( \frac{100 + \text { gain % }}{100} \right)\]
\[ = x\left( \frac{115}{100} \right)\]
\[ = \frac{23x}{20}\]
\[\text { For the second fan }, \]
\[\text { S . P = C . P }\left( \frac{100 -\text { loss % }}{100} \right)\]
\[ = \left( 3605 - x \right)\left( \frac{91}{100} \right)\]
\[\text { Since S . P of both the fans is the same, } \]
\[\frac{23x}{20} = \left( 3605 - x \right)\left( \frac{91}{100} \right)\]
\[2300x = 91\left( 72100 - 20x \right)\]
\[2300x = 6561100 - 1820x\]
\[4120x = 6561100\]
\[x = Rs . 1592 . 50\]
\[\text { Thus, C . P of the first fan is Rs } . 1592 . 50 . \]
\[\text { C . P of the second fan = Rs } . \left( 3605 - 1592 . 50 \right)\]
\[ = Rs . 2012 . 50\]
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Fill up the appropriate boxes in the following table.
| SI. No | C.P. in ₹ |
M.P. in ₹ |
S.P. in ₹ |
Discount in ₹ |
Profit in ₹ |
Loss in ₹ |
| (i) | 110 | 130 | Nil | |||
| (ii) | 110 | 130 | 10 | |||
| (iii) | 110 | 130 | 30 | |||
| (iv) | 110 | 120 | Nil | 10 | ||
| (v) | 120 | 10 | 20 | Nil |
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