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Question
A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.
Solution
et the cost price of article be Rs. x.
Then, gain percent = x
Therefore, the selling price of article
`=(x+x/100xx x)`
`=(x^2+100x)/100`
It is given that
`(x^2+100x)/100=24`
x2 + 100x = 2400
x2 + 100x - 2400 = 0
x2 + 120x - 20x - 2400 = 0
x(x + 120) - 20(x + 120) = 0
(x + 120)(x - 20) = 0
x + 120 = 0
x = -120
Or
x - 20 = 0
x = 20
Because x cannot be negative.
Thus, x = 20 is the require solution.
Therefore, the cost price of article be x = Rs. 20
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