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Question
A die is thrown once. Find the probability of getting a number greater than 2.
Solution
In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.
Total number of possible outcomes = 6
Let E be the event of getting a number greater than 2.
Then, the favourable outcomes are 3, 4, 5 and 6.
Number of favourable outcomes = 4
∴ Probability of getting a number greater than 2 = P (E) =`"Number of favourable outcomes"/"Total number of possible outcomes" = 4/6 = 2/3`
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