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Question
A die is thrown once. Find the probability of getting a number between 3 and 6.
Solution
In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.
Total number of possible outcomes = 6
Let E be the event of getting a number between 3 and 6.
Then, the favourable outcomes are 4, 5
Number of favourable outcomes = 2
∴ Probability of getting a number between 3 and 6 = P (E)= `"Number of favourable outcomes "/"Total number of possible outcomes" = 2/6 = 1/3`
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