Advertisements
Advertisements
Question
A force acts for 0.1 s on a body of mass 3.2 kg initially at rest. The force then ceases to act and the body moves through 3 m in the next one second. Calculate the magnitude of force.
Solution
Time for which force is applied =0.1 s.
Mass of the body = 3.2 kg.
Initial speed of body = 0 ms-1
After removal of forces body covers a distance of 3m in 1 second so final speed of body = 3/1 = 3ms-1.
We know FX t = m (v - u)
F X 0.1 = 3.2 (3 -0)
F = 9.6/0.1 = 96 N.
So applied force is 96 N.
APPEARS IN
RELATED QUESTIONS
A body of mass 500 g, initially at rest, is acted upon by a force which causes it to move a distance of 4 m in 2 s, Calculate the force applied.
How is the gravitational force between two masses affected if the separation between them is doubled?
A body falls from the top of a building and reaches the ground 2.5 s later. How high is the building? (Take g = 9.8 m s-2)
State unit of momentum in the SI system.
State unit of mass in CGS system.
If a number of forces act on a stationary body at the same point, then what do you conclude from it?
Why do passengers tend to fall backward when it starts suddenly?
Why do the dust particles come out of a hanging carpet when it is beaten with a stick?
An object undergoes an acceleration of 8 ms-2 starting from rest. Find the distance travelled in 5 seconds.
Name and state the action and reaction in the following case:
Firing a bullet from a gun.
