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Question
A game of chance consists of spinning an arrow, which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 and these are equally likely outcomes. Find the probability that the arrow will point at any factor of 8.
Solution
Number of all possible outcomes = 8
Let E be the event of getting any factor of 8.
These numbers are 1, 2, 4 and 8.
∴ P(arrow will point at any factor of 8) = P(E) = `"Number of outcomes favourable to"/"Number of all possible outcome" = 4/8 = 1/2`
Thus, the probability that the arrow will point at any factor of 8 is `1/2.`
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