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Tamil Nadu Board of Secondary EducationHSC Science Class 12

A garden is to be laid out in a rectangular area and protected by a wire fence. What is the largest possible area of the fenced garden with 40 meters of wire? - Mathematics

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Question

A garden is to be laid out in a rectangular area and protected by a wire fence. What is the largest possible area of the fenced garden with 40 meters of wire?

Sum

Solution


Perimeter = 40 m

2(l + b) = 40

⇒ l + b = 20

Let l = x m

b = (20 – x)m

Area = l × b

= x(20 – x)

= 20x – x2

To find the maximum area

A(x) = 20x – x2

A'(x) = 20 – 2x

A”(x) = – 2

A'(x) = 0

⇒ 20 – 2x = 0

⇒ x = 10

x = 10 is a maximum point

∴ Maximum Area = x(20 – x)

= 10(20 – 10)

= 10 × 10

= 100 sq.m.

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Applications in Optimization
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Chapter 7: Applications of Differential Calculus - Exercise 7.8 [Page 47]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 7 Applications of Differential Calculus
Exercise 7.8 | Q 4 | Page 47

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