Advertisements
Advertisements
Question
A gas cylinder contains 12 x 1024 molecules of oxygen gas.
If Avogadro’s number is 6 x 1023; Calculate:
1)The mass of oxygen present in the cylinder.
2) The volume of oxygen at S.T.P. present in the cylinder. [O = 16]
Solution
1) 1 mole oxygen molecule = 6.022 x 1023 molecules
x moles of oxygen molecule = 12 x 1024 molecules
19.93 moles of oxygen molecule = 12 x 1024 molecules.
Number moles of O2 = `("Mass of" O_2)/("Molar mass of " O_2)`
Mass of O2 = 32 x 19.93 = 637.76 g
2) 6.022 x 1023 molceules occupies 22.4 L
12 x 1024 molecules occupies = `(12 xx 10^24 xx22.4)/(6.022 xx 10^23)` = 446.36 L volume
APPEARS IN
RELATED QUESTIONS
State Avogadro's Law.
Define atomicity of a gas.
A gas cylinder contains 24 × 1024 molecules of nitrogen gas. If Avogadro's number is 6 × 1023 and the relative atomic mass of nitrogen is 14, calculate the mass of nitrogen gas in the cylinder.
Solve the following:
A vessel contains X number of molecules of hydrogen gas at a certain temperature and pressure. How many molecules of nitrogen gas would be present in the same vessel under the same conditions of temperature and pressure?
A gas cylinder contain 12 × 1024 molecules of oxygen gas
If Avogadro's number is 6 × 1023,
calculate :
(i) The mass of oxygen present in the cylinder.
(ii) The volume of oxygen at STP present in the Cylinder[O=16]
You have collected
- 2 litres of CO2
- 3 litres of chlorine
- 5 litres of hydrogen
- 4 litres of nitrogen and
- 1 litre of SO2,
under similar conditions of temperature and pressure. Which gas sample will have the greatest number of molecules? Justify your answer.
- If 150 cc of gas A contains X molecules, how many molecules of gas B will be present in 75 cc of B? The gases A and B are under the same conditions of temperature and pressure.
- Name the law on which the above problem is based.
How dose Avogadro's Law explain Gay-Lussac's Law of combining volumes?
What is the co-efficient of real expansion?
State the atomicity of Sulphur.
