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Question
A gas cylinder contains 24 × 1024 molecules of nitrogen gas. If Avogadro's number is 6 × 1023 and the relative atomic mass of nitrogen is 14, calculate the mass of nitrogen gas in the cylinder.
Solution
Nitrogen exists as N2.
Hence its molecular mass = 14 × 2 = 28 g
6 × 1023 molecules of nitrogen weigh = 28 g
24 × 1024 molecule of nitrogen will weigh = `28/(6 xx 10^23) xx 24 xx 10^24`
= 28 × 4 × 10
= 1120 g
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