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Question
A gas cylinder contains 24 × 1024 molecules of nitrogen gas. If Avogadro's number is 6 × 1023 and the relative atomic mass of nitrogen is 14, calculate the volume of nitrogen at STP in dm3.
Solution
Nitrogen exists as N2.
As 6 × 1023 molecules of nitrogen occupies = 22.4 dm3 at STP
1 molecule will occupy a volume of `222.4/(6 xx 10^23)` dm3
24 × 1024 molecules will occupy = `22.4/(6 xx 10^23) xx 24 xx 10^24`
= 895.9 dm3
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