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Question
Which of the following would occupy 22.4 litres at S.T.P.?
- 32 g of oxygen gas
- 2 moles of hydrogen gas
- 6.022 × 1023 molecules of ammonia
[Atomic weights: O = 16, H = 1, N = 14]
Options
1 and 2
1 and 3
2 and 3
1, 2 and 3
Solution
1 and 3
Explanation:
Gram molecular = 1 mole
= 6.022 × 1023 molecules
= 22.4 L
∴ Molecular Mass of \[\ce{O2}\] gas = 32 g
= 6.022 × 1023 molecules
= 22.4 L
Similary, 6.022 × 1023 molecule of \[\ce{NH3}\] = 22.4 L
Since 1 mole of any gas occupies 22.4 litres at STP, 2 moles of hydrogen gas would occupy 2 × 22.4 = 44.8 litres, which is more than 22.4 litres.
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