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What Temperature Would Be Necessary to Double the Volume of a Gas Initially at S.T.P. If the Pressure is Decreased by 50% ? - Chemistry

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Question

What temperature would be necessary to double the volume of a gas initially at s.t.p. if the pressure is decreased by 50%?

Numerical

Solution

P1 = 1 atm

P2 = `1 xx 50/100 = 1/2` atm

V1 = x cc

V2 = 2x cc

T1 = 273 K

T2 = ?

Using gas equation `("P"_1"V"_1)/"T"_1 = ("P"_2"V"_2)/"T"_2`

∴ T2 = `("P"_2"V"_2"T"_1)/("P"_1"V"_1)`

`"T"_2 = 1/2 xx (2"x" xx 273)/(1 xx "x") = 273` K

T1 = 273 - 273 = 0°C

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Standard Temperature Pressure (S.T.P.)
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Chapter 7: Study of Gas Laws - Exercise 7 (B) [Page 127]

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Selina Concise Chemistry [English] Class 9 ICSE
Chapter 7 Study of Gas Laws
Exercise 7 (B) | Q 15 | Page 127
Viraf J. Dalal Simplified ICSE Chemistry [English] Class 9
Chapter 7 Study Of Gas Laws
Additional Questions | Q 4

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