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Question
800 cm3 of gas is collected at 650 mm pressure. At what pressure would the volume of the gas reduce by 40% of its original volume, the temperature remaining constant?
Solution
Given:
V = 800 cm3
P = 654 m
P1= ?
V1 = reduced volume = 40% of 800
= `(80 xx 40)/100 = 320`
Net V1 = 800 - 320 = 480 cm3
T = T1
Using the gas equation,
`"PV"/"T" = ("P"_1 "V"_1)/"T"_1`
`(800 xx 654)/"T" = ("P"_1 xx 480)/"T"_1`
Since T = T1
`"P"_1 = (800 xx 654)/480 = 1090` mm of Hg.
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