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The equations given below relate to the manufacture of sodium carbonate (Molecular weight of Na2CO3 = 106). 1. NaCl+NHA3+COA2+HA2O⟶NaHCOA3+NHA4Cl 2. 2NaHCOA3⟶NaA2COA3+HA2O+COA2 - Chemistry

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Question

The equations given below relate to the manufacture of sodium carbonate (Molecular weight of Na2CO3 = 106).

  1. \[\ce{NaCl + NH3 + CO2 + H2O -> NaHCO3 + NH4Cl}\]
  2. \[\ce{2NaHCO3 -> Na2CO3 + H2O + CO2}\]

Equations (1) and (2) are based on the production of 21.2 g of sodium carbonate.

  1. What mass of sodium hydrogen carbonate must be heated to give 21.2 g of sodium carbonate?
  2. To produce the mass of sodium hydrogen carbonate calculated in (a), what volume of carbon dioxide, measured at STP, would be required?
Numerical

Solution

(a) \[\ce{\underset{2 × 84 = 168}{2NaHCO3} ≡ \underset{106}{Na2CO3}}\]

For obtaining 106 g of Na2CO3 amount of NaHCO3 heated = 168 g.

∴ For obtaining 21.2 g of Na2CO3 amount of NaHCO3 heated = `168/106 xx 21.2`

= 33.6 g

(b) \[\ce{\underset{84 g}{NaHCO3} ≡ \underset{22.4 litre}{CO2}}\]

84 g of NaHCO3 at STP ≡ 22.4 litre of CO2

33.6 g of NaHCO3 at STP ≡ `22.4/84 xx 33.6`

= 8.96 litre

= 8960 ml

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Standard Temperature Pressure (S.T.P.)
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Chapter 5: Mole Concept And Stoichiometry - Exercise 6 [Page 120]

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Frank Chemistry - Part 2 [English] Class 10 ICSE
Chapter 5 Mole Concept And Stoichiometry
Exercise 6 | Q 4. | Page 120
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