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The Equation Given Below Relates the Manufacture of Sodium Carbonate (Molecular Weight of Na2co3 = 106). Nacl+Nh3+ Co2+ H2o→ Nahco3+Nh4cl 2nahco3→ Na2co3+H2o + Co2 Equations (1) a - Chemistry

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Question

The equation given below relates the manufacture of sodium carbonate (molecular weight of Na2CO3 = 106).

  1. NaCl+NH3+ CO2+ H2O→ NaHCO3+NH4Cl
  2. 2NaHCO3→ Na2CO3+H2O + CO2

Equations (1) and (2) are based on the production of 21.2 g of sodium carbonate.

(a) What mass of sodium hydrogen carbonate must be heated to give 21.2 g of sodium carbonate?

(b) To produce the mass of sodium hydrogen carbonate calculate in (a), what volume of carbon dioxide, measured at S.T.P. would be required?

Answer in Brief
Sum

Solution

(a) NaCl+NH3+ CO+ H2O → NaHCO3+NH4Cl

2NaHCO3 → Na2CO3+H2O + CO2

From equation:

106 g of Na2COis produced by = 168 g of NaHCO3

So, 21.2 g of Na2COwill be produced by = 168 × 21.2/106

= 33.6 g of NaHCO3

(b) For 84 g of NaHCO3, required volume of CO2 = 22.4 litre

So, for 33.6 g of NaHCO3, required volume of CO2 = 22.4 x 33.6/84

= 8.96 litre

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Standard Temperature Pressure (S.T.P.)
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Chapter 5: Mole concept and Stoichiometry - Miscellaneous Exercises [Page 98]

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Selina Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
Miscellaneous Exercises | Q 42 | Page 98

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