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A gas cylinder contains 24 × 1024 molecules of nitrogen gas. If Avogadro's number is 6 × 1023 and the relative atomic mass of nitrogen is 14, calculate the volume of nitrogen at STP in dm3. - Chemistry

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प्रश्न

A gas cylinder contains 24 × 1024 molecules of nitrogen gas. If Avogadro's number is 6 × 1023 and the relative atomic mass of nitrogen is 14, calculate the volume of nitrogen at STP in dm3.

संख्यात्मक

उत्तर

Nitrogen exists as N2.

As 6 × 1023 molecules of nitrogen occupies = 22.4 dm3 at STP

1 molecule will occupy a volume of `222.4/(6 xx 10^23)` dm3

24 × 1024 molecules will occupy = `22.4/(6 xx 10^23) xx 24 xx 10^24`

= 895.9 dm3

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Standard Temperature Pressure (S.T.P.)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Mole Concept And Stoichiometry - Exercise 9 [पृष्ठ १२३]

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फ्रैंक Chemistry - Part 2 [English] Class 10 ICSE
अध्याय 5 Mole Concept And Stoichiometry
Exercise 9 | Q 4.1 | पृष्ठ १२३

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