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Calculate the volume of HCl gas formed and chlorine gas required when 40 ml of methane reacts completely with chlorine at S.T.P. CHA4+2ClA2⟶CHA2ClA2+2HCl - Chemistry

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प्रश्न

Calculate the volume of HCl gas formed and chlorine gas required when 40 ml of methane reacts completely with chlorine at S.T.P.

\[\ce{CH4 + 2Cl2 → CH2Cl2 + 2HCl}\]

संख्यात्मक

उत्तर

\[\ce{CH4 + 2Cl2 → CH2Cl2 + 2HCl}\]
1V         2V                                2V

From equation, 1V of CH4 gives = 2 V HCl

so, 40 ml of methane gives = 80 ml of CO2

For 1V of methane = 2V of Cl2 required

So, for 40ml of methane = 40 × 2 = 80 ml of Cl2

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Standard Temperature Pressure (S.T.P.)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Mole concept and Stoichiometry - Exercise 5A [पृष्ठ ७५]

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सेलिना Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
Exercise 5A | Q 10 | पृष्ठ ७५

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