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प्रश्न
Calculate the volume occupied by 320 g of sulphur dioxide at STP. [S = 32; O = 16]
उत्तर
Molecular weight of SO2 = 32 + (2 x 16) = 64 g
64 g of SO2 has volume = 22.4 litres
∴ 320 g of SO2 has volume = `22.4/4 xx 320`
= 112 litres
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संबंधित प्रश्न
Copper sulphate solution reacts with sodium hydroxide solution to form a precipitate of copper hydroxide according to the equation :
2NaOH + CuSO4 → Na2SO4 + Cu (OH)2 ↓
(i) What mass of copper hydroxide is precipitated by using 200 gm of sodium hydroxide?
[H = 1, O = 16, Na = 23, S = 32, Cu = 64]
(ii) What is the colour of the precipitate formed?
Determine the molecular mass of a gas if 5g of it occupy a volume of 4 L at STP.
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4NH3 + 5O2 → 4NO + 6H2O
If 27L of reactants are consumed, what volume of ni trogen monoxide is produced at the same temperature and pressure?
The equations given below relate to the manufacture of sodium carbonate (Molecular weight of Na2CO3 = 106).
- \[\ce{NaCl + NH3 + CO2 + H2O -> NaHCO3 + NH4Cl}\]
- \[\ce{2NaHCO3 -> Na2CO3 + H2O + CO2}\]
Equations (1) and (2) are based on the production of 21.2 g of sodium carbonate.
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A gas cylinder contains 24 × 1024 molecules of nitrogen gas. If Avogadro's number is 6 × 1023 and the relative atomic mass of nitrogen is 14, calculate the volume of nitrogen at STP in dm3.
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\[\ce{CH4 + 2Cl2 → CH2Cl2 + 2HCl}\]
How much volume will be occupied by 2 g of dry oxygen at 27°C and 740 mm pressure?
From the equation:
\[\ce{C + 2H2SO4 -> CO2 + 2H2O + 2SO2}\]
Calculate the volume of sulphur dioxide measured at STP, liberated at the same time.
A flask contains 3.2 g of sulphur dioxide. Calculate the following:
- The moles of sulphur dioxide present in the flask.
- The number of molecules of sulphur dioxide present in the flask.
- The volume occupied by 3.2 g of sulphur dioxide at STP
(S = 32, O = 16)
Write the values of:
standard pressure in:
(i) atm
(ii) mm Hg
(iii) cm Hg
(iv) torr
