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Question
A hemispherical bowl is made of steel 0.25 cm thick. The inside radius of the bowl is 5 cm. Find the volume of steel used in making the bowl.
Solution
Inner radius = 5cm
Outer radius = 5+0.25
Volume of steel used = outer volume – inner volume
`= 2/3×π×(R^3-r^3)`
`=2/3×22/7[5.25^3-5^3]`
=`41.282cm^3`
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