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Tamil Nadu Board of Secondary EducationHSC Commerce Class 11

a) In how many ways can 8 identical beads be strung on a necklace? b) In how many ways can 8 boys form a ring? - Business Mathematics and Statistics

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Question

  1. In how many ways can 8 identical beads be strung on a necklace?
  2. In how many ways can 8 boys form a ring?
Numerical

Solution

  1. Number of ways 8 identical beads can be stringed by `((8 - 1)!)/2 = (7!)/2`
  2. Number of ways 8 boys form a ring = (8 – 1)! = 7!

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Chapter 2: Algebra - Exercise 2.3 [Page 36]

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