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Question
A letter of English alphabets is chosen at random. Determine the probability that the letter is a consonant.
Solution
We know that, in english alphabets, there are (5 vowels + 21 consonants) = 26 letters.
So, total number of outcomes in english alphabets are, n(S) = 26
Let E = Event of choosing a english alphabet, which is a consonant
= {b, c, d, f, g, h, j, k, l, m, n, p, q, r, s t, v, w, x, y, z}
∴ n(E) = 21
Hence, required probability = `(n(E))/(n(S)) = 21/26`
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