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Question
Two different coins are tossed simultaneously. The probability of getting at least one head is
Options
\[\frac{1}{4}\]
\[\frac{1}{8}\]
\[\frac{3}{4}\]
\[\frac{7}{8}\]
Solution
When two coins are tossed simultaneously, all possible outcomes are HH, HT, TH, TT.
∴ Total number of outcomes = 4
The favourable outcomes are HH, HT, TH.
So, the favourable number of outcomes are 3.
∴ P(getting at least one head) = \[\frac{\text{ Favourable number of outcomes }}{\text{ Total number of outcomes }} = \frac{3}{4}\]
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