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Question
The probability that a number selected at random from the numbers 1, 2, 3, ..., 15 is a multiple of 4, is
Options
\[\frac{4}{15}\]
\[\frac{2}{15}\]
\[\frac{1}{5}\]
\[\frac{1}{3}\]
Solution
The total number of given numbers is 15.
∴ Total number of outcomes = 15
Among the given numbers, the multiples of 4 are 4, 8 and 12.
So, the favourable number of outcomes are 3.
∴ P(number selected is a multiple of 4) = \[\frac{\text{ Favourable number of outcomes }}{\text{ Total number of outcomes }} = \frac{3}{15} = \frac{1}{5}\]
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