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Question
A piggy bank contains hundred 50 paise coins, fifity ₹1 coins, twenty ₹2 coins and ten ₹5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, find the probability that the coin which fell will be of value more than ₹1
Solution
Total number of coins = 100 + 50 + 20 + 10 = 180
So, the total number of outcomes is 180.
A coin of value more than ₹1 can be ₹2 or ₹5 coin.
Number of ₹2 or ₹5 coins = 20 + 10 = 30
So, the favourable number of outcomes are 30.
∴ P(the coin which fell has value more than ₹1 ) = \[\frac{\text{ Favourable number of outcomes }}{\text{ Total number of outcomes }} = \frac{30}{180} = \frac{1}{6}\]
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