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Question
A magnetic flux of 8 × 10−4 weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.
Solution
Given:-
Magnetic flux linked with each turn, ϕ = 8 × 10−4 Wb
Number of turns, n = 200
Current, i = 4 A
Self-inductance is calculated as:-
\[L = \left( \frac{n\phi}{i} \right)\]
\[=\left( \frac{200}{4} \right) \times (8) \times ( {10}^{- 4} )\]
= 4 × 10−2 H
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