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Consider an infinitely long wire carrying a current I(t), with λdIdt=λ = constant. Find the current produced in the rectangular loop of wire ABCD if its resistance is R (Figure). - Physics

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Question

Consider an infinitely long wire carrying a current I(t), with `(dI)/(dt) = λ` = constant. Find the current produced in the rectangular loop of wire ABCD if its resistance is R (Figure).

Long Answer

Solution

To approach these types of problems integration is very useful to find the total magnetic flux linked with the loop.

Let us first consider an elementary strip of length l and width dr at a distance r from an infinite long current carrying wire. The magnetic field at strip due to current carrying wire is given by

`l = B(r) = (mu_0I)/(2pir) l.B(r)`

∴ Flux in strip `phi = (mu_0I)/(2pi) l int_(x_0)^x (dr)/r`

`phi = (mu_0Il)/(2pi) [log_e r]_(x_0)^x = (mu_0Il)/(2pi) log_e  x/x_0`

`ε = (-dphi)/(dt)`

So `IR = (dphi)/(dt)`

`I = 1/R d/(dt) [(mu_0Il)/(2pi) log_e  x/x_0] = (mu_0l)/(2piR) . log_e  x/x_0 (dl)/(dt)`

`I = (mu_0λl)/(2piR) log_e  x/x_0`  .....`[because (dl)/(dt) = λ (given)]`

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Chapter 6: Electromagnetic Induction - MCQ I [Page 38]

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NCERT Exemplar Physics [English] Class 12
Chapter 6 Electromagnetic Induction
MCQ I | Q 6.25 | Page 38

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