मराठी

Consider an infinitely long wire carrying a current I(t), with λdIdt=λ = constant. Find the current produced in the rectangular loop of wire ABCD if its resistance is R (Figure). - Physics

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प्रश्न

Consider an infinitely long wire carrying a current I(t), with `(dI)/(dt) = λ` = constant. Find the current produced in the rectangular loop of wire ABCD if its resistance is R (Figure).

दीर्घउत्तर

उत्तर

To approach these types of problems integration is very useful to find the total magnetic flux linked with the loop.

Let us first consider an elementary strip of length l and width dr at a distance r from an infinite long current carrying wire. The magnetic field at strip due to current carrying wire is given by

`l = B(r) = (mu_0I)/(2pir) l.B(r)`

∴ Flux in strip `phi = (mu_0I)/(2pi) l int_(x_0)^x (dr)/r`

`phi = (mu_0Il)/(2pi) [log_e r]_(x_0)^x = (mu_0Il)/(2pi) log_e  x/x_0`

`ε = (-dphi)/(dt)`

So `IR = (dphi)/(dt)`

`I = 1/R d/(dt) [(mu_0Il)/(2pi) log_e  x/x_0] = (mu_0l)/(2piR) . log_e  x/x_0 (dl)/(dt)`

`I = (mu_0λl)/(2piR) log_e  x/x_0`  .....`[because (dl)/(dt) = λ (given)]`

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पाठ 6: Electromagnetic Induction - MCQ I [पृष्ठ ३८]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 12
पाठ 6 Electromagnetic Induction
MCQ I | Q 6.25 | पृष्ठ ३८

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