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A man borrows Rs. 6,000 at 5% C.I. per annum. If he repays Rs. 1,200 at the end of each year, find the amount of the loan outstanding at the beginning of the third year. - Mathematics

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Question

A man borrows Rs. 6,000 at 5% C.I. per annum. If he repays Rs. 1,200 at the end of each year, find the amount of the loan outstanding at the beginning of the third year.

Sum

Solution

Given that the amount borrowed = Rs. 6,000.

Rate per annum = 5%

Interest on Rs. 6,000 = `5/100` × Rs. 6,000 = Rs. 300

So, amount at the end of the first year = Rs. 6,000 + Rs. 300 = Rs. 6,300

Amount left to be paid = Rs. 6,300 - Rs. 1,200 = Rs. 5,100.

Interest on Rs. 5,100 = `5/100` × Rs. 5,100 = Rs. 255

So, amount at the end of the second year = Rs. 5,100 + Rs. 255 = Rs. 5,355.

Amount left to be paid = Rs. 5,355 - Rs. 1,200 = Rs. 4,155.

Hence, the amount of the loan outs tan ding at the beginning of the third year is Rs. 4,155.

shaalaa.com
Concept of Compound Interest - Compound Interest as a Repeated Simple Interest Computation with a Growing Principal
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Chapter 2: Compound Interest (Without using formula) - Exercise 2 (B) [Page 33]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 2 Compound Interest (Without using formula)
Exercise 2 (B) | Q 4 | Page 33
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