मराठी

A man borrows Rs. 6,000 at 5% C.I. per annum. If he repays Rs. 1,200 at the end of each year, find the amount of the loan outstanding at the beginning of the third year. - Mathematics

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प्रश्न

A man borrows Rs. 6,000 at 5% C.I. per annum. If he repays Rs. 1,200 at the end of each year, find the amount of the loan outstanding at the beginning of the third year.

बेरीज

उत्तर

Given that the amount borrowed = Rs. 6,000.

Rate per annum = 5%

Interest on Rs. 6,000 = `5/100` × Rs. 6,000 = Rs. 300

So, amount at the end of the first year = Rs. 6,000 + Rs. 300 = Rs. 6,300

Amount left to be paid = Rs. 6,300 - Rs. 1,200 = Rs. 5,100.

Interest on Rs. 5,100 = `5/100` × Rs. 5,100 = Rs. 255

So, amount at the end of the second year = Rs. 5,100 + Rs. 255 = Rs. 5,355.

Amount left to be paid = Rs. 5,355 - Rs. 1,200 = Rs. 4,155.

Hence, the amount of the loan outs tan ding at the beginning of the third year is Rs. 4,155.

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Concept of Compound Interest - Compound Interest as a Repeated Simple Interest Computation with a Growing Principal
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Compound Interest (Without using formula) - Exercise 2 (B) [पृष्ठ ३३]

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सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 2 Compound Interest (Without using formula)
Exercise 2 (B) | Q 4 | पृष्ठ ३३

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