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Question
A man is double his son's age. Twenty years ago, he was six times his son's age. Find the present age of the father and the son.
Solution
Let the present age of the son be x years.
Then, the man's age = 2x years.
20 years ago, their ages will be (x - 20)years and (2x - 20)years respectively.
Given, Twenty years ago, son was six times his son's age.
As per given conditions,
`((x - 20))/((2x - 20)) = (1)/(6)`
⇒ 6x - 120 = 2x - 20
⇒ 4x = 100
⇒ x = 25 years.
⇒ y = 50 years.
Thus, the present age of the son is 25 years.
Then, the man's age = 50 years.
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