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Question
A mechanic can open a nut by applying a force of 200 N while using a lever handle of 50 cm length. How long handle is required if he wants to open it by applying a force of only 50 N?
Solution
Given force applied by a mechanic, F = 200 N
length of ever, d = 50 cm = 0.5m
Torque, τ F x d = 200 x 0.5 = 100Nm
Now, if the mechanic applies a force, F' = 50N
let d'be the length of the lever to produce the same torque.
the, τ = F' x d'
⇒ d' = `100/50` = 2 m
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