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A Metal Cube of Edge 12 Cm is Melted and Formed into Three Smaller Cubes. If the Edges of the Two Smaller Cubes Are 6 Cm and 8 Cm, Find the Edge of the Third Smaller Cube. - Mathematics

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Question

A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edges of the two smaller cubes are 6 cm and 8 cm, find the edge of the third smaller cube.

Answer in Brief

Solution

Let the edge of the third cube be x cm .

Three small cubes are formed by melting the cube of edge 12 cm . 

Edges of two small cubes are 6 cm and 8 cm . 

\[\text { Now, volume of a cube = (side ) }^3 \]

\[\text { Volume of the big cube = sum of the volumes of the three small cubes }\]

\[ \Rightarrow (12 )^3 = (6 )^3 + (8 )^3 + (x )^3 \]

\[ \Rightarrow 1728 = 216 + 512 + x^3 \]

\[ \Rightarrow x^3 = 1728 - 728 = 1000\]

\[ \Rightarrow x = \sqrt[3]{1000} = 10 cm\]

\[ \therefore \text { The edge of the third cube is 10 cm } .\]

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Chapter 21: Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - Exercise 21.4 [Page 30]

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RD Sharma Mathematics [English] Class 8
Chapter 21 Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube)
Exercise 21.4 | Q 16 | Page 30

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