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Question
A metal rod AB of length 80 cm is balanced at 45 cm from the end A with 100 gf weights suspended from the two ends.
- If this rod is cut at the centre C, then compare the weight of AC to the weight of BC.
- Give a reason for your answer in (a).
Solution
- Weight of AC < weight of BC.
-
Even though the weights present are the same at both ends, the torque arm of B is less than the torque arm of A. This means the moment of the weight of the rod acts from side B and the C.G. lies beyond 45. Thus, more weight is concentrated between C to B.
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