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Question
A nucleus \[\ce {^A_Z X}\] emits 2 α particles and 1 β particles to form a nucleus \[\ce {^222_85 R}\]. Find the atomic nucleus and mass number of X.
Solution
\[\ce{^A_ZX ->[-α] ^{A-4}_{Z-2}X_1 -> ^{A-4-4}_{Z-2-2}X_2 ->[-β]^{A-8}_{Z-4+1}R}\]
After emitting two alpha particles
Atomic number = Z - 4
Mass number = A - 8
After emitting a beta particle
Atomic number = Z - 4 + 1
mass number = A - 8
Final atomic number = 85
85 = Z - 4 + 1
Z = 88
Final mss number 222
222 = A - 8
A = 230
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