English

A person wanted to sell a scooter at a loss of 25%. But at the last moment he changed his mind and sold the scooter at a loss of 20%. If the difference in the two SP’s is ₹ 4000 - Mathematics

Advertisements
Advertisements

Question

A person wanted to sell a scooter at a loss of 25%. But at the last moment he changed his mind and sold the scooter at a loss of 20%. If the difference in the two SP’s is ₹ 4000, then find the CP of the scooter.

Sum

Solution

Let the cost price of the scooter be ₹ x

If he sells the scooter at a loss of 25%, then

SP = x – 25% of x = `x - 25/100x` = ₹ `75/100x`

and if he sells the scooter at a loss of 20%, then

SP = x – 20% of x = `x - 20/100x` = ₹ `80/100x`

It is given that the difference in the two SP's is ₹ 4000

∴ `80/100x - 75/100x` = 4000

⇒ `(80x - 75x)/100` = 4000

⇒ `(5x)/100` = 4000

⇒ x = `(4000 xx 100)/5` = ₹ 80000

Hence, cost price of scooter is ₹ 80000.

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Comparing Quantities - Exercise [Page 208]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 7
Chapter 7 Comparing Quantities
Exercise | Q 111. | Page 208

Video TutorialsVIEW ALL [1]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×