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Question
A plane of a coil of 10 turns is tightly wound around a solenoid of diameter 2 cm having 400 turns per centimeter. The relative permeability of the core is 800. Calculate the inductance of the solenoid.
Solution
Given:
N = 10, d = 2 cm = 0.02 m
N = 400 turns/cm = 4 × 104 turns/m
μr = 800
To find: Inductance of solenoid (L)
Formulae:
- μ = μrμ0
- N = nl
- L = μn2l `((pi"d"^2)/4)`
Calculation:
From formula (i), (ii) and (iii),
L = μrμ0nN`((pi"d"^2)/4)`
= `(800 xx 4pi xx 10^-7 xx 4 xx 10^4 xx 10 xx pi xx 0.02^2)/4`
= 0.1264 H
The inductance of the solenoid is 0.1264 H.
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