English

A racing car has a uniform acceleration of 4 m s−2. What distance will it cover in 10 s after start? - Science

Advertisements
Advertisements

Question

A racing car has a uniform acceleration of 4 m s−2. What distance will it cover in 10 s after start?

Sum

Solution

Acceleration (a) = 4 ms−2

Time (t) = 10s

Initial velocity (u) = 0

second equation of motion

s = `ut + (1/2) at^2` 

s = `0 xx 10 + (1/2) xx 4 xx 10^2`

s = 200 m

Hence the distance covered by the car after 10 s = 200 m

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Motion - Intext Questions [Page 110]

APPEARS IN

NCERT Science [English] Class 9
Chapter 8 Motion
Intext Questions | Q 4 | Page 110

RELATED QUESTIONS

A trolley, while going down an inclined plane, has an acceleration of 2 cm s−2. What will be its velocity 3 s after the start?


A stone is thrown in a vertically upward direction with a velocity of 5 m s-1. If the acceleration of the stone during its motion is 10 m s-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?


An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.


Multiple choice Question. Select the correct option.

A driver applies brakes when he sees a child on the railway track, the speed of the train reduces from 54 km/h to 18 km/h in 5 s. What is the distance travelled by train during this interval of time?


A boy drops a stone from a cliff, reaches the ground in 8 seconds. Calculate

  1. final velocity of stone
  2. height of cliff. (Take g = 9.8 ms−2)

A stone thrown vertically upwards takes 4 s to return to the thrower. Calculate

  1. initial velocity of the stone
  2. maximum height attained by stone. (Take g = 10 ms−2)

A spaceship is moving in space with a velocity of 50 kms−1. Its engine fires for 10 s, such that its velocity increases to 60 kms−1. Calculate the total distance travelled by a spaceship in 1/2 minute, from the time of firing its engine


Derive the equations
(i) v= u+at and
(ii) v2-u2= 2as, where the symbols have their usual meanings.


Derive the equation
V2-u2 = 2as


A body starts to slide over a horizontal surface with an initial velocity of 0.5 ms−1. Due to friction, its velocity decreases at the rate of 0.05 ms2. How much time will it take for the body to stop?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×