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Question
A ray of light, incident on an equilateral prism `(μ_g = sqrt3)`moves parallel to the base line of the prism inside it. Find the angle of incidence for this ray.
Solution
It is given that the prism is equilateral in shape. So, all the angles are equal to 60°.
Thus, the angle of prism, A = 60°
The angle of refraction in case of a prism, `r =A/2 = 30°`
We can now apply Snell’s law
So,
μa sin i = μg sin r
Here, μa → refractive index of air, n1 = 1
μg → refractive index of glass,`n_2 =sqrt3`
i → angle of incidence
Thus,
`sin i = ((mug)/mu_a) sin r ((mug)/mu_a) sin 30° `
`sin i = sqrt3/2`
So, the angle of incidence is
i =60°
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